Five exterior angles of a hexagon are 41° 32°,67º 71°, and 55°, What is the measure of the sixth exterior
angle
Can yo help me
As they both are vertical angles, their magnitude would be same
3x - 25 = 6x - 80
6x - 3x = 80 - 25
3x = 55
x = 55/3
In short, Your Answer would be 55/3
Hope this helps!
Answer:
Theta = 0, 60 degrees.
Step-by-step explanation:
2 sin^2 theta + 3 cos theta = 3
Using the identity sin ^2 theta = 1 - cos^2 theta :
2(1 - cos^2 theta) + 3 cos theta = 3
2 - 2cos^2 theta) + 3 cos theta = 3
2 cos^2 theta - 3 cos theta + 3 - 2 = 0
2 cos^2 theta - 3 cos theta + 1 = 0
(2 cos theta - 1)(cos theta - 1) = 0
cos theta = 1/2 , cos theta = 1
Theta = 60 degrees or theta = 0
Answer:
Cientos means hundreds in Spanish.