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3 years ago

Can someone plz help me with this one problem plz!!!!!

Mathematics

2 answers:

docker41 [41]3 years ago

8 0

Answer:

Step-by-step explanation:

y=6x so

if x=0 y=0 because 6*0=0

if x=1 y=6 because 6*1=6

so on so

6*2=12=y

6*3=18=y

6*4=24 (if there is...)

anyanavicka [17]3 years ago

5 0

Answer:

Ive listed the answers below

Step-by-step explanation:

x y

0 0

1 6

2 12

3 18

4 24

5 30

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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

Write a ratio, in the simplest form and a percent for the shaded area (there's a 5x4 box and 6 cubes are shaded)

Alexxandr [17]

Answer:

$\%Percent = 30 \%$

Step-by-step explanation:

Given

$Shaded = 6\ cubes$

$Box = 5\ x\ 4$

Required

Determine the percentage of the shaded cubes

First, we calculate the number of boxes:

$Box = 5\ x\ 4$

Express as multiplication

$Box = 5\ *\ 4$

$Box = 20$

This implies that there are 20 cubes in the box.

The percentage of the shaded cubes is:

$\%Percent = \frac{Shaded}{Box} * 100\%$

$\%Percent = \frac{6}{20} * 100\%$

$\%Percent = \frac{6* 100}{20} \%$

$\%Percent = \frac{600}{20} \%$

$\%Percent = 30 \%$

30% were shaded

5 0

2 years ago

In which number does the digit 4 have a value that is \dfrac{1}{10} 10 1 start fraction, 1, divided by, 10, end fraction times

MrRissso [65]

Answer:

The digit 4 should be in the thousand position in the number sought;

Examples

9.304,

9.004

Step-by-step explanation:

Here, we are required to consider decimal places of numbers

The digit 4 in the number 3.8463 is in the hundredth position

That is 0.04

We are asked to look for the number with a digit 4 that has the same value as $\frac{1}{10} \times$ the digit 4 in 3.8463

That is

$\frac{1}{10} \times 0.04 = 0.004$

Therefore, the digit 4 in the number sought should be in the thousandth position, that is 0.004

Example includes 9.304 or 9.004.

4 0

3 years ago

Which of the following vectors are orthogonal to (1,5)? Check all that apply

Andre45 [30]

We know that
If the scalar product of two vectors is zero, both vectors are orthogonal

A. (-2,5)
(-2,5)*(1,5)-------> -2*1+5*5=23-----------> are not orthogonal

B. (10,-2)
(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal

C. (-1,-5)
(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal

D. (-5,1)
(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal

the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)

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2 years ago

What the exact decimal equivalent of 7/12

OleMash [197]

Answer: The decimal is 0.583

Step-by-step explanation:

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3 years ago