Answer:
yes
Step-by-step explanation:
but really nice to the world I'm happy for you because you is so buetiful
For the answer to the question above, I'll show my solution for the answer below.
Area A = pi r^2
<span>The rate of change of area = d A/ d t = 2 pi r d r/d t </span>
<span>r= 2t, d r = 2 d t </span>
<span>This gives </span>
<span>d A/ d t = 2 pi 2t 2 d t = 8 pi t dt </span>
<span>Integrate it </span>
<span>A= 4 pi t^2. </span>
<span>After t=5, the area will be 100* 3.14 square= 314 square units.</span>
Answer:
Always
Step-by-step explanation:
An acute angle is an angle that is less than 90. Supplementary angles add up to 180.
So 180-89= 91
An obtuse angle is any angle that is greater than 90.
Here's a link to a better explanation.
brainly.com/question/14180317
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
__
<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
__
<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
1. You have that:
- The trapezoids are similar.
- The larger base of the smaller trapezoid is 18 m and its area is 310 m².
- The larger base of the larger trapezoid is 32 m.
2. Then:
Sides=18/32
Sides=9/16
Area=(9/16)²
Area=81/256
3. Now, you can find the area of the larger trapezoid, as below:
81/256=310/x
81x=(310)(256)
x=79360/81
x=980 m²
Therefore, the answer is: The area of the larger trapezoid is 980 m².
