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3 years ago

Simplify the expression (3x4 + 9x3 – 7x + 15) + (-6X4 – 8x2 + 5x – 3)

Mathematics

1 answer:

elena-s [515]3 years ago

5 0

Answer:

If the numbers next to the "x" are "carroted" ( ^ ) then the answer is

-3x^4 + 9x^3 -8x^2 -2x +12

Step-by-step explanation:

Basically, you just add the like terms together.

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Richard simplified an expression in three steps, as shown:

soldi70 [24.7K]

Answer:

Step 2 because Richard multiply the powers of same base in denominator instead adding powers of same base.

Step-by-step explanation:

We are given that Richard simplified an expression in threes steps

We have to find the incorrect step in simplification of Richard

Step 1: all the exponent are multiplied by 3

$\frac{x^{-4}y^2}{yx^2\cdot x^2y^{-4}}^{3}=\frac{x^{-12}y^6}{y^3x^6\cdot x^6y^{-12}}$

Step 2:The exponents in the denominator are multiplied

$\frac{x^{-12}y^6}{y^3x^6\cdot x^6 y^{-12}}=\frac{x^{-12}y^6}{x^{12}y^{-9}}$

Step 3:The exponents of the same base are subtracted during division

$\frac{x^{-12}y^6}{x^{12}y^{-9}}=x^{-12-12}y^{6+9}$

$=x^{-24}y^{15}$

Richard makes mistake in step 2 when we multiply then power of same base should be added but Richard multiply the powers of same base in denominator.

4 0

4 years ago

The diameter of 0 gauge copper wire is 8.252 mm. Find the resistance (in ω) of a 2.40 km length of such wire used for power tran

VashaNatasha [74]

d = diameter of the copper wire = 8.252 mm

r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m

A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶

L = length of the copper wire = 2.40 km = 2400 m

ρ = resistivity of copper wire = 1.68 x 10⁻⁸

resistance of copper wire is given as

R = ρL/A

inserting the above values in the formula

R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)

R = 0.753 ohm

8 0

4 years ago

Help! Pls :(((((((((((

Law Incorporation [45]

The answer is 22 because you replace the x with 5 and do 5x 5 - 3

4 0

3 years ago

What is 30% of 70?? please help

melamori03 [73]

Answer:

Step-by-step explanation:

<em>Method 1:</em>

$p\%=\dfrac{p}{100}\\\\30\%=\dfrac{30}{100}=\dfrac{3}{10}=0.3\\\\30\%\ of\ 70\ is\\\\0.3\cdot70=21$

<em>Method 2:</em>

$\begin{array}{cccc}100\%&-&70&\text{divide both sides by 10}\\\\10\%&-&7&\text{multiply both sides by 3}\\\\30\%&-&21\end{array}$

4 0

4 years ago

Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time be

Arte-miy333 [17]

Answer:

a) We know that the distribution for X is given by: $X \sim Unif (a=10, b=45)$

The density function for this distirbution is given by:

$f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45$

So then the height of the uniform density curve would be given by:

$h = \frac{1}{35}= 0.029$

b) For this case we want to calculate the following probability:

$P(X\leq 20)$

And we can use the cumulative distribution function given by:

$F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45$

And we can calculate the probability like this:

$P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286$

Step-by-step explanation:

For this case we define our random variable X="Lindsay's late arrival time, in minutes"

Part a

We know that the distribution for X is given by: $X \sim Unif (a=10, b=45)$

The density function for this distirbution is given by:

$f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45$

So then the height of the uniform density curve would be given by:

$h = \frac{1}{35}= 0.029$

Part b

For this case we want to calculate the following probability:

$P(X\leq 20)$

And we can use the cumulative distribution function given by:

$F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45$

And we can calculate the probability like this:

$P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286$

7 0

4 years ago