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Anettt [7]
3 years ago
9

Please help me with this question

Mathematics
1 answer:
boyakko [2]3 years ago
5 0

Answer:

0.7999989281

Step-by-step explanation:

x1 = cos^-1 (3/5)

x1= 53.13°

sin(53.13) = 0.7999989281

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Five years ago Janeta age was one_fifth of her mother'sage .Now she is one_third of her mother's age.Find their present ages?
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Answer:

J - Janeta's age  M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

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then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Step-by-step explanation:

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Step-by-step explanation:

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