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Furkat [3]
3 years ago
11

The half-life of strontium -90 is approximately 29 Year’s . How much of a 150 g sample of strontium-90 will remain after 116 yea

rs
Mathematics
1 answer:
marin [14]3 years ago
3 0
The half-life is 29 years.
116 : 29 = 4
So we will have 4 periods of half-life:
( 1/2 )^4 = 1/16
150 g * 1/16 = 9.375 g
Answer:
9.375 g of strontium -90 will remain after 116 years.
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the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of
NeX [460]
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
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8 0
3 years ago
Read 2 more answers
I really need help <br> it’s very hard
barxatty [35]

Answer:

The angle ZLK has a value of 75 degrees.

Step-by-step explanation:

We can calculate this as:

m\angle MLZ+m\angle ZLK=m\angle MLK\\\\(x+66)+(x+86)=130\\\\2x+152=130\\\\2x=130-152\\\\x=-22/2=-11\\\\\\m\angle ZLK=x+86=-11+86=75

We replace the angles values in the equation, as both angles that are formed with Z (MLZ and ZLK), when added, gives as the angle MLK. This allows us to calculate x. The value for x is -11.

Then, with the value for x we can calculate any of both angles.

6 0
3 years ago
Help pleaseeee!!!!!!
coldgirl [10]

Answer:

18. 46

19. 0.7

22. 4 3/4

23. 54.5

26. 14

27. 11.5

31. 15

etc.

Step-by-step explanation:

absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:

absolute value of 46  =  46

absolute value of - 36 = 36

(imagine the sign in front of the # isn't there)

4 0
3 years ago
For a certain map, the scale shows that 1 cm on the map equals 2.50 km on earth's surface. two towns on the map are 4.75 cm apar
Julli [10]
<span>In this problem, to find the answer we have to setup a series of ratios that relate the scale to real life distance. We know that 1cm = 2.50km, so that ratio would be 1cm/2.5km. For two towns that are 4.75cm apart on the map, we set a ration of 4.75cm/x km, where x is the actual distance. Now we set the ratios equal to each other and solve for x. 1/2.5=4.75/x where x = 4.75*2.5/1 = 11.875 and rounding up we get 11.88 km. The two towns are actually 11.88 km apart from each other.</span>
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Jared has two dogs, Spot and Rover. Spot weighs 75.25 pounds. Rover weighs 48.8 pounds more than Spot. How much does Rover weigh
Luda [366]
75.25+ 48.8=124.05 so rover weighs 124.05 pounds hope this helps☺
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