1. The average yards gained per play was 10.56
2. The total amount of yards recorded was 450.8 yards
I hope this helps you
tan (13.180/8)
tan (2340/8)
tan(292,5)
-2,41
Answer:
Step-by-step explanation:
<em>Refer to attached</em>
- Height of plants (h) >> Frequency >> Midpoint >> Frequency x midpoint
- 0 <h < 10 >> 1 >> 5 >> 5
- 10 <h < 20 >> 4 >> 15 >> 60
- 20 <h < 30 >> 7 >> 25 >> 175
- 30 <h < 40 >> 2 >> 35 >> 70
- 40 <h < 50 >> 3 >> 45 >> 135
- 50 <h < 60 >> 3 >> 55 >> 165
Sum of frequencies = 20
Sum of frequency x midpoint product = 610
<u>Mean height </u>
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
