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Sergeu [11.5K]
3 years ago
9

HELP PLEASEEEEE I suck at mathhh!!!

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
The answer is d. Look at the equation , there isn’t a line under the > sign, so you don’t need to pick the graph with a colored circle, and then there are 3 left that are not colored. Those are b,c and d. Now, the > sign does to the right ( the pointy part) so your line had to go to the right. Only d is like that. Hope this helps and can you make me brainliest?
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Write an expression that represents the value, in cents, if n nickels.
Mademuasel [1]
1, 10, 25, 50, and so on...
8 0
2 years ago
HELP ME PLZ :( its similar triangles you can pick both neither or one of the triangles
Sauron [17]

Answer:

A is the answer

Step-by-step explanation:

because it is equal to the first triangle

3 0
2 years ago
What is the slope of the line through (-9,6) and (-6,-9)
Juliette [100K]

\text{The slope formula:}\ m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have:}\\(-9;\ 6)\to x_1=-9;\ y_1=6\\(-6;\ -9)\to x_2=-6;\ y_2=-9\\\\\text{substitute:}\\\\m=\dfrac{-9-6}{-6-(-9)}=\dfrac{-15}{-6+9}=\dfrac{-15}{3}=-5

Answer: m = -5

7 0
3 years ago
Eight members of the Math club equally shared three pizzas. Expressed as a fraction,whAt part of a pizza did each member receive
Vera_Pavlovna [14]
3/8 of a pizza.

If you divide each pizza into eight parts, each member would receive 1/8 of one pizza. Since there are three pizzas, each member would receive three 1/8 of a pizza, or 3/8.

You can prove this answer by multiplying 3/8 by 8, to get 24/8 simplified to 3.
4 0
3 years ago
When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic
Elanso [62]

Answer:

95% Confidence interval for the mean

142.8 \leq\mu\leq158.4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

cf=\sqrt{\frac{N-n}{N-1} }

The standard deviation can be estimated as

\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963

The 95% confidence interval has a z value of 1.96, so it becomes:

M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4

5 0
3 years ago
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