To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

$\boxed{ \sf \: area \: of \: square =side ^{2} }$

Side 3 metre

$\rm \implies \: area = 3 ^{2}$

$\rm \implies9$

<em>Thus, The area of 1st square is 9m²...</em>

The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

Length = 6m
Breadth = 7+3=10m

$\sf \: area \: of \: rectangle = length \times breadtg$

$\tt \dashrightarrow \: area = 10 \times 3$

$\tt \dashrightarrow \: area = 30m ^{2}$

<em>Thus, The area of rectangle is 30m²....</em>

Now, Add area of all the figures to get the total area.

$\bf \:total \: area = 9 + 9 + 30 \\ \bf= 48m {}^{2}$

<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>

8 0

2 years ago

Jill is calculating the standard deviation for her test grades. Mrs. Brown tells her that she did not take into account the curv

AlexFokin [52]

B is the answer. I hope this helps.

8 0

4 years ago