3 years ago

Grade 7 Math 7. Can anyone help me answer this question? I want the correct answers. No, guessing.

1 answer:

algol133 years ago

6 0

Part one of your questions would be 1/20
Part two would be 1/20
Part three. Yes they are equal
Part four. None of them sense there equal

You might be interested in

Solve and receive brain list

liberstina [14]

Answer:

y=2

x=-1

Step-by-step explanation:

2x-4y=-10

-2x-y=0

Add Together and get:

-5y=-10

y=2

put the 2 in for y in either equation to solve for x

2x-4(2)=-10

2x-8=-10

2x=-2

x=-1

3 0

3 years ago

Write the first five terms of the the sequence defined by the explicit formula an=72(1/3)^n-1

lisabon 2012 [21]

$a_n=72\left(\dfrac{1}{3}\right)^{n-1}\\\\\text{Put}\ n=1,\ n=2,\ n=3,\ n=4,\ n=5\ \text{to the equation}:\\\\n=1\to a_1=72\left(\dfrac{1}{3}\right)^{1-1}=72\left(\dfrac{1}{3}\right)^0=72(1)=72\\\\n=2\to a_2=72\left(\dfrac{1}{3}\right)^{2-1}=72\left(\dfrac{1}{3}\right)^1=72\left(\dfrac{1}{3}\right)=\dfrac{72}{3}=24\\\\n=3\to a_3=72\left(\dfrac{1}{3}\right)^{3-1}=72\left(\dfrac{1}{3}\right)^2=72\left(\dfrac{1}{9}\right)=\dfrac{72}{9}=8\\\\n=4\to a_4=72\left(\dfrac{1}{3}\right)^{4-1}=72\left(\dfrac{1}{3}\right)^3=72\left(\dfrac{1}{27}\right)=\dfrac{72}{27}=\dfrac{8}{3}\\\\n=5\to a_5=72\left(\dfrac{1}{3}\right)^{5-1}=72\left(\dfrac{1}{3}\right)^4=72\left(\dfrac{1}{81}\right)=\dfrac{72}{81}=\dfrac{8}{9}\\\\Answer:\ \boxed{72,\ 24,\ 8,\ \dfrac{8}{3},\ \dfrac{8}{9}}$