Find the missing length of the triangle 12 8 Y

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

What does the triangle look like?

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Use the geometric series 5^Ž (8)*-* to answer each question.

ella [17]

Answer:

First one is:

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Second one is:

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Evgesh-ka [11]

Prove: $\frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)} = tan(x)$

$LHS = \frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)}$

$cos(2x) = 1 - 2sin^{2}(x) = 2cos^{2}(x) - 1$
$sin(2x) = 2sinxcosx$

$LHS = \frac{1 - 1 + 2sin^{2}(x) + 2sinxcosx}{1 + 2cos^{2}(x) - 1 + 2sinxcosx}$
$= \frac{2sinx(sinx + cosx)}{2cosx(cosx + sinx)}$
$= \frac{2sinx}{2cosx}$
$= tanx = RHS$

$\therefore \frac{1 - cos(2x) + sin(2x)}{1 + cos(2x) + sin(2x)} = tan(x)$

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2 years ago

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iVinArrow [24]

Answer:

-1 1/2 and -1 3/4 on the number line.

Step-by-step explanation:

First you find -1 on the number line. Then you add 1/2 which is also 2/4. You find it by going two places from -1 to the right.

Then you do the same for -1 3/4. You start at -1 and move 3 places to the right.

3 0

3 years ago

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