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3 years ago

Write the equation 0.3x^2+5x-7=0 in standard form and then choose the value of “b”

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

Answer:

b = 5

Step-by-step explanation:

The given equation is :

$0.3x^2+5x-7=0$ .......(1)

It is in the form of quadratic equation. The general form of a quadratic equation is as follows :

$ax^2+bx+c=0$ .....(2)

Comparing equations (1) and (2), we get :

a = 0.3, b = 5 and c = -7

Hence, the value of b is equal to 5.

You might be interested in

Six years less than Tracey's age as an expression

likoan [24]

Answer:

T-6=X

Step-by-step explanation:

Tracey = T

X = Awnser

If we are subtracting six from Tracey's age, you would subtract six from T

since we don't know Tracey's age, it is represented by T.

Hope this Helps!

4 0

3 years ago

If m<mkl=83. m<jkl=127. and m<jkm=(9x-10). find the value of x

kirza4 [7]

MKL = 83, JKL = 127, JKM = 9x - 10 given

JKL + MKL = JKM angle addition postulate

127 + 83 = 9x - 10 substitution

210 = 9x - 10 simplify (add like terms)

220 = 9x addition property of equality

$\frac{220}{9}$ = x

3 0

3 years ago

Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.33$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$\sigma = 5, n = 100$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.33*\frac{5}{\sqrt{100}} = 1.165$

So the correct answer is:

1.165.

6 0

3 years ago

Ahmad wants to practice free-throws. He estimates the distance from the free-throw Line to the hoop and marks it with chalk. Ahm

const2013 [10]

Answer: 10%

Step-by-step explanation:

The difference between his estimated and actual distance is 15 - 13.5 = 1.5

The percentage of error is the difference divided by the actual value.

1.5÷15 = 0.10

Converted to a percentage, it is 10%

4 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago