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denis-greek [22]
3 years ago
6

NEED ANSWERS ASAP PLEASE

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer:

8

Step-by-step explanation:2 times 2 times 2

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Ahmed and Karnia are building scenery of the Egyptian pyramids out of plywood for a community play. They pyramids are represente
Arlecino [84]
A.)
 
The first thing we must do for this case is to find the area of ​​the complete figure.
 We have then:
 Triangle 1:
 A1 = (1/2) * (1.5) * (1)
 A1 = 0.75 feet ^ 2
 Triangle 2:
 A2 = (1/2) * (1.5) * (2)
 A2 = 1.5 feet ^ 2
 Triangle 3:
 A3 = (1/2) * (0.75) * (1)
 A3 = 0.375 feet ^ 2
 Rectangle:
 A4 = (5) * (0.75)
 A4 = 3.75 feet ^ 2
 Adding the areas we have:
 A = A1 + A2 + A3 + A4
 A = 0.75 + 1.5 + 0.375 + 3.75
 A = 6.375 feet ^ 2
 Answer:
 there are 6,375 feet ^ 2 of plywood in the scenery

 B.)
 
Triangles:
 A = A1 + A2 + A3
 A = 0.75 + 1.5 + 0.375
 A = 2,625 feet ^ 2
 Two layers of paint:
 A = 5.25 feet ^ 2 <45 feet ^ 2
 Rectangle:
 A = 3.75 feet ^ 2
 Two layers of paint:
 A = 7.5 feet ^ 2 <45 feet ^ 2
 Answer:
 
One quart of each color is needed.
5 0
4 years ago
You have been asked to analyze the popcorn recipes of three different local theatres in order to figure out which theatre has th
svlad2 [7]

Answer:    The ratio value of oil to popcorn kernels for theatre C is 6 / 32 = 3 / 16.

Step-by-step explanation: Given that the manager of Theatre A says that they usually go through about 15 cups of popcorn kernels and about 5 cups of oil each weeknight.

Then, the ratio value of oil to popcorn kernels for theatre A is 5 / 15 = 1 / 5.

Given that the manager of Theatre B says that they order 18 cups of oil and 72 cups of popcorn kernels each week.

Then, the ratio value of oil to popcorn kernels for theatre B is 18 / 72 = 1 / 4.

Given that the manager of Theatre C says that their concessions use 6 cups of oil and 32 cups of popcorn kernels on a busy Saturday.

Then, the ratio value of oil to popcorn kernels for theatre C is 6 / 32 = 3 / 16.

3 0
2 years ago
Use the quadratic formula to solve x^2+8x+9=0
Tju [1.3M]
None of your options, not via complete the square nor quadratic the formula.

Solve for x over the real numbers:
x^2 + 8 x + 9 = 0

x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2

sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2

(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)

(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:

Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________

Solve for x:
x^2 + 8 x + 9 = 0

Subtract 9 from both sides:
x^2 + 8 x = -9

Add 16 to both sides:
x^2 + 8 x + 16 = 7

Write the left hand side as a square:
(x + 4)^2 = 7

Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)

Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)

Subtract 4 from both sides:
Answer:  x = sqrt(7) - 4 or x = -4 - sqrt(7)
4 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
I’m still trying to do my work and trying to figure out this
swat32
The slope of a vertical line is undefined, D.

If you were to try to solve use something like the rise over run method, you would end up with a 0 in the denominator. Since dividing by 0 gives you an undefined result, the slope would be undefined.
3 0
3 years ago
Read 2 more answers
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