How can you find approximations (estimations) of square roots?

2 answers:

6 0

By finding these tables, you can use them to locate the square root of numbers 1 to 100. Choose or make a method to find an approximate square root of each number. Then Round your answer to the nearest tenth.

Luda [366]4 years ago

3 0

To find approximations of square roots, you should find the nearest prefect square. For example if your looking to approximate the square rot of 10, the closest perfect square is 9 and the square root of that is three. Thus, you can say that the square root is about 3. Hope this helps and please mark brainiest. :D

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7 0

3 years ago

How do I use substitution to solve a system of linear equations?

Pachacha [2.7K]

Answer:

the substitution method is one way to solve linear equation. the substitution method is when substitute the one y value with the other:

example :

x+y=10

y=10-x ( value of y)

2x+y=12 ( substitute the value of y in the equation )

2x+(10-x)=12

2x+10-x=12 ( now solve for x)

x=12-10

x=2 ( substitute the value of x in the equation x+y=10)

x+y=10

2+y=10

y=10-2

y=8

( i hope it helps)

8 0

3 years ago

I am so stuck! :( Pls help me!!! I don't get the problem and I don't know how to solve it

Lelu [443]

Answer:

$\frac{n^{2}}{2a}$

Step-by-step explanation:

Just split it up first $\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}$
Then 9 divided by 18 can be simplified into the fraction 1/2
What can go into $a$ and $a^2$ ? a itself right, so if you divide a by a you get 1, if you divide $a^2$ by a you get a
Same as the a fraction, if you divide $n^3$ by n you get $n^2$
$\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}=\frac{1}{2}\times \frac{1}{a} \times\frac{n^2}{1}=\frac{n^{2}}{2a}$