Answer:
The answer to this question is given in the explanation section. The correct option is long tail
Explanation:
a.Folksonomy
Folksonomy is a way of organizing data and digital content. With Web 2.0, users can collaboratively manage and tag photos, journals and other media. As more users do this, creates a system of classification for the media and information. so this option is not correct
b. long tail (correct option)
Some sites are able to offer services as well in which users can subscribe monthly or pay a fee every so often. An example of this would be Netflix.
c.user participation
All users have the free will to contribute to the site which makes many Web 2.0 pages public. With sites such as Wikipedia, anyone is open to the editing of articles. Information is provided two-way instead of solely from the site owner.
d.application
Web 2.0 applications that allow anyone to create and share online information or material they have created. As you know that there are number of different types of web 2.0 applications including wikis, blogs, social networking, folksonomies, podcasting & content hosting services.
Answer:
Text Editor
Explanation:
What the question implies is that, what tool will she need to create the website.
And the answer is a text editor; this is so because the other three options are web development languages used in developing a website but the text editor is where she'll write her line of codes to create the required website poll.
Example of usable text editors are notepad and notepad++ etc.
Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output
You hit ctrl than the plus/equal sign Hope that helped!
