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satela [25.4K]
3 years ago
8

In the range C15:G15, insert a function to calculate the total daily revenue. In the range H11:H15, insert a function to calcula

te the weekly totals for the seating categories and grand total.
Computers and Technology
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

1. =SUM(C15: G15) 2. The first part of second part is =SUM(C11:G11), =SUM(C12:G12), =SUM(C13:G13), =SUM(C14:G14), =SUM(C15:G15).  Last is total revenue and the first four are seating for various classes and the second part of the second question is =SUM(H11: H14)  which is the grand total of seats.

Explanation:

Suppose from C15 to G15, we have five columns and hence five days. So we can have one column for one day, and add there, number of seats. C15: G15 is daily revenue, and C11: G11 ...... C14: G14 is the number of seats each day, and in each class, and thus the above answer. We can have different assumptions, and formula will change according to assumptions. You can use HLOOKUP as well if you want.

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6.25 (Prime Numbers) A positive integer is prime if it’s divisible by only 1 and itself. For example, 2, 3, 5 and 7 are prime, b
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Answer:

  1. public class Main {
  2.    public static void main (String [] args) {
  3.        for(int i = 2; i < 10000; i++){
  4.            if(isPrime1(i)){
  5.               System.out.print(i + " ");
  6.            }
  7.        }
  8.        System.out.println();
  9.        for(int i = 2; i < 10000; i++){
  10.            if(isPrime2(i)){
  11.                System.out.print(i + " ");
  12.            }
  13.        }
  14.    }
  15.    public static boolean isPrime1(int n){
  16.      
  17.        for(int i=2; i <= n/2; i++){
  18.            if(n % i  == 0){
  19.                return false;
  20.            }
  21.        }
  22.        return true;
  23.    }
  24.    public static boolean isPrime2(int n){
  25.        for(int i=2; i <= Math.sqrt(n); i++){
  26.            if(n % i  == 0){
  27.                return false;
  28.            }
  29.        }
  30.        return true;
  31.    }
  32. }

<u></u>

Explanation:

Firstly, create the first version of method to identify a prime number, isPrime1. This version set the limit of the for loop as n/2. The for loop will iterate through the number from 2 till input n / 2 and check if n is divisible by current value of i. If so, return false to show this is not a prime number (Line 22 - 26). Otherwise it return true to indicate this is a prime number.

In the main program, we call the isPrime1 method by passing the i-index value as an argument within a for-loop that will iterate through the number 2 - 10000 (exclusive).  If the method return true, print the current i value). (Line 5 - 9)

The most direct way to ensure all the prime numbers below 10000 are found, is to check the prime status from number 2 - 9999 which is amount to 9998 of numbers.

Next we create a second version of method to check prime, isPrime2 (Line 31 - 40). This version differs from the first version by only changing the for loop condition to i <= square root of n (Line 33).  In the main program, we create another for loop and  repeatedly call the second version of method (Line 13 - 17). We also get the same output as in the previous version.

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