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3 years ago

Find the area please

Mathematics

2 answers:

wel3 years ago

4 0

Answer: d.

Step-by-step explanation: 7x15= 105x5= 525

Shtirlitz [24]3 years ago

3 0

Answer:525 to find area multpi all sides

Step-by-step explanation: can i have brainlst since i helped you

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ANTONII [103]

Answer:

15 batteries.

Step-by-step explanation:

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3 years ago

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Alona [7]

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4 years ago

A manufacturer of pharmaceutical products analyzes specimens from each batch of a product to verify the concentration of the act

Alisiya [41]

Answer:

$0.82-2.977\frac{0.048}{\sqrt{15}}=0.783$

$0.82+2.977\frac{0.048}{\sqrt{15}}=0.857$

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 0.82$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.048 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.977$

Now we have everything in order to replace into formula (1):

$0.82-2.977\frac{0.048}{\sqrt{15}}=0.783$

$0.82+2.977\frac{0.048}{\sqrt{15}}=0.857$

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

5 0

3 years ago

If the sides of a square are increased by 2 inches, the area becomes 25 squares inches. Find the length of sides of the original

Mumz [18]

You know that the sides of a square are increased by 2 inches: the expression should be written as (x+2)

The area is 25 square inches

The area of a square is s×s or s²

so it can be solved as:

(x+2)²=25

$(\sqrt{x+2})^{2} =\sqrt{25}$

x+2=5

x=3

<u>The length of the original side is 3 inches</u>

Hope it helps!

8 0

2 years ago