Ask question

Ask question

All categories

2 years ago

9

How do you multiply monomials with the same base?

1 answer:

IrinaK [193]2 years ago

3 0

9514 1404 393

Answer:

multiply their coefficients, use the base with the sum of exponents

Step-by-step explanation:

The coefficients multiply. The base gets an exponent that is the sum of the exponents of the factors.

(a·x^b)(c·x^d) = ac·x^(b+d)

_____

If you remember that an exponent is simply an indicator of the number of times the base is a factor, this should be fairly clear. The usual associative and commutative properties of multiplication apply.

<u>Example</u>

5x^2 · 7x^3= 5·x·x·7·x·x·x

= 5·7·x·x·x·x·x

= (5·7)(x^(2+3))

= 35x^5

You might be interested in

The new book was only $19.50 but it was another 60% if the author signed it. What will my book cost with an author's signature.

Andrej [43]

So if you take 10% of $19.50, you have $1.95. If you multiply $1.95 by 6, you get $11.70 which is 60% of the original cost of the book. Add $11.70 to $19.50 and you have $31.20.

7 0

3 years ago

254 cm to inches with explanation please

sdas [7]

Answer:

100 inch

Step-by-step explanation:

1 cm=0.394 inch

254 cm×0.394=100 inch

4 0

3 years ago

Read 2 more answers

The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere

tatuchka [14]

Answer:

a

The null hypothesis will be $H_o : \mu = 60 \ kg$

b

The alternative hypothesis will be $H_a : \mu < 60$

c

The alternative hypothesis will be $H_a : \mu > 60$

d

The alternative hypothesis will be $H_a : \mu \ne 60$

e

left; right; both

Step-by-step explanation:

Considering question a

The body weight of the colt is $\mu = 60 \ kg$

The null hypothesis will be $H_o : \mu = 60 \ kg$

Considering question b

Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be $H_a : \mu < 60$

Considering question c

Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be $H_a : \mu > 60$

Considering question d

Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be $H_a : \mu \ne 60$

Considering question e

For question b , the corresponding p-value will be on the left because the average weight is less than 60 kg

For question c , the corresponding p-value will be on the right because the average weight is more than 60 kg

For question d , the corresponding p-value will be on both because the average weight is different from 60 kg

5 0

2 years ago

Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a) = f(b). f(x) = cot x/

nydimaria [60]

$cot(x/2)$ is not differentiable over the interval $[ \pi, 7\pi]$

3 0

3 years ago

Juan analyzes the amount of radioactive material remaining in a medical waste container over time. He writes the function f(x) =

forsale [732]

I believe this is right

5 0

3 years ago

Read 2 more answers