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fiasKO [112]
3 years ago
5

Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a) = f(b). f(x) = cot  x/

2 [π, 7π]
Mathematics
1 answer:
nydimaria [60]3 years ago
3 0
cot(x/2) is not differentiable over the interval [ \pi,  7\pi]
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The quadratic function f(x) = 2x² – 44x + 185 is written in vertex form is f(x) = 2(x –  11)² – 57.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

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Take common 2 from the equation, we have

f(x) = 2(x^2 - 22x )+ 185

Add and subtract 121, we have

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And we know that the standard equation

f(x) = a(x - h)² + k

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The vertex (h, k) is (11, -57).

More about the quadratic equation link is given below.

brainly.com/question/2263981

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