Answer:
Option A
Step-by-step explanation:
Domain should be greater than/equal to 1 for the function to be one-one.
f has vertex at (1,0)
f inverse has (0,1)
f(x) = 4
(x - 1)⁴ = 4
x = 2.414
On f: (2.414, 4)
On f inverse: (4, 2.414)
Gradient of line,m=(17-6)/(20-0)=11/20
finding equation of line using a point (20,17)
y-17=11/20(x-20)
y-17=(11/20x)-11
y=11/20x+(17-11)
y=(11/20)*x+6
Answer:
p = 16/9
Step-by-step explanation:
We write the equation in the form of directional.
y -1 = 6x ⇔ y = 6x + 1
y - 1 = 3x ⇔ y = 3x + 1
y - 7 = 2x - 6 ⇔ y = 2x - 6 + 7
y = 2x + 1
y - 7 = x - 2 ⇔ y = x - 2 + 7
y = x + 5
Equations cleverly arranged .
Point Q = (0,1)
b factor , not only fits the last equation
In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1
Answer b
We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function
The result of equations confirmed our choice Answer b
Answer:
55
Step-by-step explanation:
JL = JK + KL
84 = 3x+5 + 6x+7
Combine like terms
84 = 9x +12
Subtract 12 from each side
84-12 = 9x+12-12
72 = 9x
Divide by 9
72/9 = 9x/9
8 =x
We want KL
KL = 6x+7
6*8 +7
48+7
55
