Answer:
Step-by-step explanation:
We need to find the conditional probability P( T1 < s|N(t)=1 ) for all s ≥ 0
P( time of the first person's arrival < s till time t exactly 1 person has arrived )
= P( time of the first person's arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
{ As till time t, we know that exactly 1 person has arrived, thus relevant values of s : 0 < s < t }
P( time of the first person arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
= P( exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
P(exactly x person has arrived till time t ) ~ Poisson(kt) where k = lambda
Therefore,
P(exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
= [ kse-ks/1! ] / [ kte-kt/1! ]
= (s/t)e-k(s-t)
Answer:
a = 4
Step-by-step explanation:
Answer:
The missing side length is 5
Step-by-step explanation:
Basically 32 to 4 and 56 to 7 is 8 to 1, so you divide 40 by 8 to get the answer, 5
Simplify the left side.
Tap for more steps...
3−9x=2(−4x+7)
Simplify the right side.
Tap for more steps...
3−9x=−8x+14
Move all terms containing x
to the left side of the equation.
Tap for more steps...
3−x=14
Move all terms not containing x
to the right side of the equation.
Tap for more steps...
−x=11
Multiply each term in x=−11
by −1
Tap for more steps...
x=−11
Hope this helps!
Answer:yeeyyh
Step-by-step explanation:
