P = IRT
T=P/(IR)
hope helped
Answer:
Jamar should hit the wall opposite to the side of the barrier(if there is a space), which will cause the ball to bounce off the wall at an angle and into Target.
Use either the distance formula or the Pythagorean Theorem. i suggest you plot the 2 given points and draw the line segment CD connecting these points.
What is the horiz. distance between the 2 points? The vertical distance?
If you'd square the horiz. distance and also square the vertical distance, and then add these two squares together, and finally take the positive square root of this sum, you'll have the distance cd. Round it off to the nearest tenth.
Answer:
$29.70
Step-by-step explanation:
when she opened her account she opened it with $900.00 she will get 2.2% interest per year. she leaves it for 1 1/2 years. what you do it you multiply 900.00 x 2.2% that will give you $19.80 then you have to divide it by 2 and that will give you 9.90. then you add 9.90 + 19.80 = 29.70
900. x 2.2% = 19.80
19.80 divide by 2 = 9.90
9.90 + 19.80 $ 29.70
35a. We're asked to compute the ratio between the enlarged width and the original width. So we literally perform the operation:
![6.5\div 3.5 \approx 1.86](https://tex.z-dn.net/?f=6.5%5Cdiv%203.5%20%5Capprox%201.86)
35b. If the order is wrong the image would be shrunk instead of enlarged, with a ratio of ![3.5\div 6.5](https://tex.z-dn.net/?f=3.5%5Cdiv%206.5)
36. We know that
![\dfrac{p}{q}=\dfrac{2}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7Bq%7D%3D%5Cdfrac%7B2%7D%7B3%7D)
Observe that
![\dfrac{6p}{2q}=\dfrac{6}{2}\cdot\dfrac{p}{q}=3\cdot\dfrac{p}{q}=3\cdot\dfrac{3}{2}=\dfrac{9}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B6p%7D%7B2q%7D%3D%5Cdfrac%7B6%7D%7B2%7D%5Ccdot%5Cdfrac%7Bp%7D%7Bq%7D%3D3%5Ccdot%5Cdfrac%7Bp%7D%7Bq%7D%3D3%5Ccdot%5Cdfrac%7B3%7D%7B2%7D%3D%5Cdfrac%7B9%7D%7B2%7D)