No. Using the address will get you either the default site, or the first site declared. Web servers can host VirtualHosts, and rely on the site name to know which VirtualHost to serve. TMI, it's called name based virtual host, as opposed to the machine having many addresses then address based virtual hosts can be created.
While: <span> the loop must repeat until a certain "condition" is met. If the "condition" is FALSE at the beginning of the loop, the loop is never executed. The "condition" may be determined by the user at the keyboard. The "condition" may be a numeric or an alphanumeric entry. <span>This is a good, solid looping process with applications to numerous situations.
</span></span><span>while:<span>int ctr = 1;
while (ctr < = 20)
{
cout<< ctr++ <<"\n";
}
</span><span>
</span><span>
</span><span>HOPE i HELPED! brainliest? :D </span></span>
Answer:
Therefore the inverse function of
is 
Explanation:
We need to find the inverse of function 
Function Inverse definition :







Simplify














Therefore the inverse function of
is 
Answer: Defined
, Controllable
, Measured
, Effective
, Institutionalized are some of the characteristics needed to be exhibited by an organisation to improve its software process
Explanation:
Software process improvement(SPI) helps in achieving goals of software products for an organization. Some of its characteristics are Defined
, Controllable
, Measured
, Effective
, Institutionalized.
It goals must be defined, and must also be controlled and it performance must be measured at regular intervals and any reforms carried out to achieve goals must be effective. Lastly it should implement all goals in an institutional framework to be followed by every one in the organization.