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Phantasy [73]
3 years ago
6

What is the rate of change of the liner equation below

Mathematics
2 answers:
nikdorinn [45]3 years ago
5 0
These are the answers:
x is going up 2
y is going up 6
Doss [256]3 years ago
3 0
X is going up 2
y is going up 6
hope it helps 
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If the example is y= -2x and y= x+3 Does the point (2,5) make either equation true?
skelet666 [1.2K]

Answer:

the second one is true

Step-by-step explanation:

5=-4. 2nd one 5=5

3 0
3 years ago
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The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
2 years ago
Find the x- and y- intercepts of 2x -2y = -6
Sonbull [250]

2x-2y=-6

-2y= -2x-6

y=x+3

Y-intercept= 3

X-intercept= -3

8 0
3 years ago
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Help Geometry only help on even numbers check if correct
kompoz [17]

Answer:

everything is correct

Step-by-step explanation:

you did a good job

8 0
2 years ago
In how many different ways can 4 students be seated with in a row?
DanielleElmas [232]
<span>4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.</span>
8 0
3 years ago
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