In this item, we are not given with the choices for the ordered pair which could be the solution to the given equation. What can be done is to assume a value for one of the variables and solve for the other. To be able to find one that satisfies let x be equal to zero and substitute to the given equation.
-3(0) - 7y = 37
Simplifying,
-0 - 7y = 37
The value of y from the equation is 37/7. Thus, one of the ordered pairs that satisfies the equation is,
(0, 37/7)
Answer:
1:6
this is because 6 kiwis + 30 fruits = 36 fruits. Then you have 6 kiwis and 36 fruits. therefore the ratio is 6:36. when you simplify , it becomes 1:6
Answer:
40.25 if my math is right
Step-by-step explanation:
I think that the missing value is 16m.
I just multiplied two other numbers with 20 and 20 x 16 x 16 = 5120
I hope this was right.
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032