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MrRissso [65]
3 years ago
13

A protein has altered funtion as a result of a single amino acid substition in the polypeptide (protein). this change resulted f

rom what type of mutation?
Biology
1 answer:
Rzqust [24]3 years ago
3 0
The answer is <span>missense.</span>
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Plants and animals that live in estuaries face a dilemma in maintaining water balance inside their cells. During high tide they
jok3333 [9.3K]

Answer:

The correct answer is "a hypertonic solution".

Explanation:

Seawater is the most clear example of a hypertonic solution in nature. The concentration of ions in seawater are far more superior than the concentration of ions inside a plant or an animal cell, since seawater have an osmolarity of about 1000 mOsm/l. Therefore, at high tide a plant or animal cell will be in a hypertonic solution, and the cells must have adaptions to avoid cell shrinking and dead.

6 0
3 years ago
Some students at a middle school conducted a laboratory investigation to learn more about the physical properties of different e
TiliK225 [7]

Answer:

A

Explanation:

1. The colour is non metallic.

2. properties of metal solidness is not there, because of results of hammer experiment.

3. Physical consistency is not solid.

Etc.

4 0
3 years ago
In what ways are the new cells (daughter cells), which result from a cell cycle, similar?
slava [35]
Recycling cells division. meoisis theroy
6 0
3 years ago
A woman with type A blood (whose father was type O) has children with a man that has type O blood. Both individuals are heterozy
Fantom [35]

Answer:

Explanation:

A woman with type A blood (whose father was type O) meaning her genotype is AO mates with

Man that has type O blood (OO genotype)

Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.

Cross

A O M N H h

O AO OO M MM MN H HH Hh

O AO OO N MN NN h Hh hh

Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4

Type A with M antigen:

1/2*1/4*3/4 = 3/32

Type A with M and N antigens:

1/2*1/2*3/4 = 3/16

Type A with N antigen:

1/2*1/4*3/4 = 3/32

Type O with M antigen:

1/2*1/4*3/4= 3/32

Type O with M and N antigens:

1/2*1/2*3/4 = 3/16

Type O with N antigen:

1/2*1/4*3/4 = 3/32.

The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).

8 0
3 years ago
While studying for your physical anthropology midterm, your classmate tells you that the bones of Lucy, a famous australopitheci
ludmilkaskok [199]

Answer:

This specimen is also far too old for C-14 dating to be accurate, as well as for any other technique but palaeomagnetic dating.

Explanation:

The second part of the sentence is not accurate, since the remains were dated by uranium-lead dating. Carbon-14 dating measures ages in the tens of thousands of years, and uranium-lead dating measures in the millions to billions of years.

8 0
3 years ago
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