Please help!! look at the picture as well!!

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

4 0

Answer: i’m sorry please mark me a thanks i really need help with a school project and i need points to ask a question i hope you have a good day

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You had a bag of fruit snacks that you shared with 4 friends. Each of you got at least 2 fruit snacks. The inequality x/ 5 ≥ 2 m

podryga [215]

Answer:

10 fruit snacks were in the packet.

Step-by-step explanation:

lets look at the numbers, we have 5 and 2. your answer is 8 because 5x2=10

it would basiclly be the same as dividing. say your question was you have a packet of fruit snacks, there are 10 fruit snacks in the packet and 4 friends and you how many did you each have the answer would be 2.

your probably wondering why its 5 and not 4 well the question says... You had a bag of fruit snacks that you shared with 4 friends, it says you shared so that is why its 5 and not 4.

HOPE THIS HELPS!!!!!! :)

6 0

3 years ago

Sam wants to buy 8 pencils and 6 pens, which cost a total of $8.50. He realizes he doesn't have enough cash and instead takes on

Brums [2.3K]

Let x be the price of each pen and y be the price of each pencil. From the given, the equations that are described are,
6x + 8y = 8.50
4x + 4y = 5
Solving for x and y simultaneously gives an answer of x = 0.75 and y = 0.5.

Thus, each pen costs $0.75 and each pencil costs $0.50.

8 0

3 years ago

Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2

d1i1m1o1n [39]

$\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
\\
g_{avg}=\frac{g(7)-g(3)}{7-3}\\
\\
=\frac{4-1}{4}\\
\\
=\frac{3}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}$

$\\(ii)\\ \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
\\
f_{avg}=\frac{f(7)-f(3)}{7-3}\\
\\
=\frac{0-5}{4}\\
\\
=\frac{-5}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}$

$\\(iii)\\
\text{Since g(4)=5, so we have}\\
\\
f(g(4))=f(5)\\
\\
\text{since the value of f is 1 at x=5. so }\\
\\
f(g(4))=f(5)=1\\
\\
\text{hence we have, }f(g(4))=$ 1

$\\(iv)\\
\text{Since f(3)=5, so we have}\\
\\
g(f(3))=g(5)\\
\\
\text{since the value of g is 2 at x=5. so }\\
\\
g(f(3))=g(5)=2\\
\\
\text{hence we have, }g(f(3))=$ 2