All categories

2 years ago

Please help!! look at the picture as well!!

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

4 0

Answer: i’m sorry please mark me a thanks i really need help with a school project and i need points to ask a question i hope you have a good day

You might be interested in

Just want to double check our answer.

bearhunter [10]

0 divided by 2 is 0.

You can use the multiplicative identity property: the product of any number and zero is still zero.

Hope this helped :)

3 0

3 years ago

NEED HELP NOW 100 POINTS WILL MARK BRAINLIEST ANSWER!!!! 2 photos below PLZ ANSWER BOTH CORRECTLY

slega [8]

The first answer is C.
The second answer is A.

7 0

2 years ago

Read 2 more answers

How do i plot this can you please help me

marusya05 [52]

Do the left side first but make sure to label each point according to the numbers. Then in the right side, you will follow the instructions connecting the numbers you wrote in from the left side. It will form your pic.

3 0

3 years ago

2/3 cup of oatmeal is needed to make 10 granola bars. How many such granola bars can be made with 20 cups of oatmeal ?

Firlakuza [10]

30 granola bars
20/1×3/2= 30
~JZ
Hope it helps

5 0

3 years ago

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

Step 1: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

Step 2: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

Step 3: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

Step 4: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

Step 5: There is enough evidence to support the claim that the population mean is greater than 100.

Alternatively: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0

3 years ago