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lana66690 [7]
3 years ago
12

7/3+3(2/3−1/3)*2 I need an answer to this question really quick, and by the way the two in the end is a second power

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
7 0

Answer:

\frac{8}{3}

Step-by-step explanation:

Given

\frac{7}{3} + 3(\frac{2}{3} - \frac{1}{3} )²

= \frac{7}{3} + 3 (\frac{1}{3} )²

= \frac{7}{3} + 3 × \frac{1}{9}

= \frac{7}{3} + \frac{1}{3}

= \frac{8}{3}

melomori [17]3 years ago
7 0

Answer:

8/3

Step-by-step explanation:

7/3+3(2/3-1/3)^2

=7/3+3(1/3)^2

=7/3+3(1/9)

=7/3+3/9

=7/3+1/3

=8/3

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F (x) = (x + 5)^3(x - 9)(x + 1)
Lostsunrise [7]

Answer:

F (x) = (x + 5)^3(x - 9)(x + 1)  = 5

Step-by-step explanation:

Hope this helps! :)

4 0
3 years ago
An element with a mass of 810 grams decays by 29.3% per minute. To the nearest minute, how long will it be until there are 10 gr
lakkis [162]

Answer:

13

Step-by-step explanation:

i got it wrong but this was the correct answer

6 0
3 years ago
Our class has 50 students. Assuming that no students are born on leap days (February29), what is the probability that no two stu
madreJ [45]

Answer:  a) \dfrac{799}{31250}  b) \dfrac{30451}{31250}

Step-by-step explanation:

Since we have given that

Number of days in a year = 365

Number of students = 50

Probability that no two students share the same birthday. It means each student has different birthday.  

Probability(no two students share the same birthday)=\dfrac{365-1}{365}\times \dfrac{365-2}{365}........\times \dfrac{365-50}{365}

Probability(no two students share the same birthday)=\dfrac{^{365}P_{50}}{365^{50}}

Probability(no two students share the same birthday)=\dfrac{799}{31250}\approx 0.025568

Probability that at least one of the students has the same birthday as another student in the class is given by

1-P(\text{no student share the same birthday})\\\\=1-\dfrac{799}{31250}\\\\=\dfrac{30451}{31250}=0.974432

5 0
3 years ago
What is the side length of the eectagkes
dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

<u>1. 5 in and 1/3 in</u>

Here,

Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2

<u>2. 5 in and 4/3 in</u>

Here,

l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2

<u>3. 5/2 in and 4/3 in</u>

let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2

<u>4. 7/6 in and 6/7 in</u>

<u>Let</u>

l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2

<u>Hence,</u>

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

8 0
3 years ago
Please help!!!<br> will pick brainliest
olga55 [171]

Answer:

circumference is 81.68

area is 530.93

Step-by-step explanation:

C=2πr=2·π·13≈81.68141

A=πr2=π·132≈530.92916

8 0
3 years ago
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