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Lunna [17]
2 years ago
10

What is the sum of the fraction below? 1/7+3/8

Mathematics
1 answer:
Ksivusya [100]2 years ago
8 0

Answer:

  \frac{29}{56}

Step-by-step explanation:

Take LCM of 7 and 8 to make the denominators same.

LCM = 56

and then solve :

      \frac{1}{7} + \frac{3}{8} = \frac{(1 \times 8) + (3 \times 7)}{7 \times 8} = \frac{29}{56}

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Will give brainliest need help asap
sergiy2304 [10]

Answer:

I'll only answer the 1st one:    17 cubed / square root of 12

Step-by-step explanation:

Figure the rest out yourself.

6 0
2 years ago
Solve the Integral of 1/(1-y2)
Eva8 [605]
<span>−<span>1/<span><span>(<span>y+1</span>)</span><span>(<span>y<span>−1</span></span>) is the answer</span></span></span></span>
5 0
3 years ago
Joe is trying to soup up his dragster. He knows that the time needed for the car to go from 0 to 100 miles per hour varies inver
inysia [295]
8 seconds

The hardest part of this is setting up the equation -- the calculations are pretty easy.

You're told that the time (needed to go from 0 to 100 MPH) is inversely proportional to the horsepower:  what this means is that as horsepower gets larger, time gets smaller. This makes sense since the more horsepower you have, the less time it will take you to get to 100 MPH

You can think of this as:

200 HP = 10 seconds
250 HP = x seconds

You set the equation up as:

250 HP / 200 HP = 10 sec / x sec

Now, just cross multiply and solve:

250 / 200 = 10 / x
250x = (200 x 10)
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x = 2000 / 250
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So, as you increase the horsepower from 200 to 250, the time decreases from 10 seconds to 8 seconds.

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3 0
3 years ago
What is 7/10 divided by 2
vodka [1.7K]

Answer:

7/20

Step-by-step explanation:

7/10 ÷ 2/1 is the same as 7/10 * 1/2 which is 7/20

3 0
3 years ago
Given the function f(x) = 4^x - 1, explain and show how to find the average rate of change between x = 1 and x = 4.
soldier1979 [14.2K]

Answer:

84

Step-by-step explanation:

f(1)=4^1 - 1 = 3

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rate of change = \frac{f(x_2)-f(x_1)}{x_2-x_1}

(255 - 3) / (4 - 1) = 252 / 3 = 84

3 0
3 years ago
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