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sergey [27]
3 years ago
9

Solve this equation. 25) v - 6(4v + 6) = -82

Mathematics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

v = 2

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

v - 6 (4v + 6) = -82

Distribute:

v + (-6) (4v) + (-6) (6) = -82

v + -24v + -36 = -82

Combine 'like' terms:

(v  -24v) + (-36) = -82

-23v - 36 = -82

Next, you'll want to add 36 to both sides of the equation.

-23v-36 + 36 = -82 + 36

-23v = -46

Finally, divide both sides by -23.

\frac{-23v}{-23} = \frac{-46}{-23}

v = 2

I hope this helped you! Leave a comment below if you have any further questions! :)

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Answer:

(1) 20%

Step-by-step explanation:

→ Find the difference in price

200 - 160 = 40

→ Divide difference by original price

40 ÷ 200 = 0.2

→ Multiply the answer by 100

0.2 × 100 = 20%

7 0
3 years ago
Parallel lines m and n are cut by a transversal t. Which two angles are corresponding angles? A. 1 and 5 B. 1 and 6 C. 1 and 2 D
jeka94

Answer:

1 and 5

Step-by-step explanation:

So basically corresponding angles are the angles which lie on the same line of the transversal

And also one of them will be an interior angle and the other a exterior angle

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3 years ago
V = bdt. Solve the formula for b.
levacccp [35]

Answer:

b = \frac{V}{dt}

Step-by-step explanation:

Divide both sides by dt, so it cancels out.

\frac{V}{dt} = \frac{bdt}{dt}

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3 0
3 years ago
An arrow is shot vertically upward from a platform 20 ft high at a rate of 179ft / s * e When will the arrow hit the ground ? Us
MissTica

The height attained by the arrow is modelled as,

h(t)=-16t^2-v_{\circ}t+h_{\circ}

Given that the initial height is 20 ft and the initial velocity is 179 ft per second,

\begin{gathered} v_{\circ}=179 \\ h_{\circ}=20 \end{gathered}

Substitute the values,

\begin{gathered} h(t)=-16t^2-(179)t+(20) \\ h(t)=-16t^2-179t+20 \end{gathered}

When the arrow hits the ground its height will become zero,

\begin{gathered} h(t)=0 \\ -16t^2-179t+20=0 \end{gathered}

Applying the quadratic formula,

\begin{gathered} t=\frac{-(-179)\pm\sqrt[]{(-179)^2-4(-16)(20)}}{2(-16)} \\ t=\frac{179\pm\sqrt[]{33321}}{-32} \\ t=\frac{179\pm182.54}{-32} \\ t=\frac{179+182.54}{-32},t=\frac{179-182.54}{-32} \\ t=-11.298,t=0.1106 \end{gathered}

Since time cannot be negative, we have to neglect the negative value.

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1 year ago
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Pepsi [2]

Answer:

c = 17

Step-by-step explanation:

a^2 + b^2 = c^2

= 8*8 + 15*15

= 64 + 225

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= 289 SQUARED

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5 0
3 years ago
Read 2 more answers
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