Equiangular Triangles can only have acute angles. True or false?
1 answer:
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Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
We will have to use proportions:
Cross multiplying we get
Now divide:
Solve to tenths place we get
The woman casts a 36.6 ft long shadow.
Cross multiplying we get
Now divide:
Solve to tenths place we get
The woman casts a 36.6 ft long shadow.