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TEA [102]
3 years ago
6

Explain how to determine whether a point is a solution to a linear inequality?

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:The solution of a linear inequality in two variables like Ax + By > C is an ordered pair (x, y) that produces a true statement when the values of x and y are substituted into the inequality.

Example

Is (1, 2) a solution to the inequality

2x+3y>1

2⋅1+3⋅2>?1

2+5>?1

7>1

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.

Step-by-step explanation:

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An illusionist needs up to 10 volunteers for a show. She needs no fewer than 4 female volunteers. Let x represent the number of
Sliva [168]

The <em><u>correct answers</u></em> are:

B- x + y ≤ 10 ; and D- x ≥ 4

Explanation:

The illusionist needs at least 4 female volunteers.  This means he could use 4 or more; this means x, the number of female volunteers, is greater than or equal to 4:

x ≥ 4

The total of number of volunteers needed is up to 10.  This means the illusionist can use 10 or fewer people; this means the total is less than or equal to 10.

The number of female volunteers is x and the number of male volunteers is y; together they create the expression x+y.  This gives us

x+y ≤ 10

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frez [133]

True.  If they never intersect then they must have the same slope and are parallel

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Ghella [55]

Answer:

√(2 + √3)/4

Step-by-step explanation:

Sine 5π/12 = Sine (5π/6)/2

Recall

π = 180°

Thus,

Sine (5π/6)/2 = Sine (5×180 /6)/2

= Sine 150/2

Recall

Sine θ/2 = √(1 – Cos θ)/2

Thus,

Sine 150/2 = √(1 – Cos 150)/2

But, Cosine is negative in the 2nd quadrant. Thus,

Cos 150 = – Cos 30 = –√3/2

Thus,

√(1 – Cos 150)/2 = √(1 – –√3/2 )/2

= √(1 + √3/2 )/2

= √[(2 + √3)/2 ÷ 2]

= √[(2 + √3)/2 × 1/2]

= √(2 + √3)/4

Therefore,

Sine 5π/12 = √(2 + √3)/4

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