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mariarad [96]
3 years ago
8

Please help me I do not understand what to do​

Mathematics
2 answers:
fgiga [73]3 years ago
7 0

Answer:

3 7/12

Step-by-step explanation:

There are 12 inches in 1 feet. So 43 inches would be 43/12=3 7/12 feet.

anyanavicka [17]3 years ago
3 0
What they said bleh
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15 and 17 pls.. 15 points!!!!
Maurinko [17]

Step-by-step explanation:

15) 50 ÷ 2 = 25

17) Mean = 301, Mode = 40-50

(10+20) ÷ 2 = 15, (20+30) ÷ 2 = 25, (30+40) ÷ 2 = 35

(40+50) ÷ 2 = 45, (50+60) ÷ 2 = 55, (60+70) ÷ 2 = 65

(70+80) ÷ 2 = 75

• 15×4 = 60, 25×8 = 200, 35×10 = 350, 45×12 = 540

55×10 = 550, 65×4 = 260, 75×2 = 150

Mean = (60+200+350+540+550+260+150) ÷ 7

= 2110 ÷ 7

= 301.4285....

= 301

Mode : the highest frequency

3 0
3 years ago
Read 2 more answers
Write 18 1/4 as a decimal ​
nevsk [136]

Answer:

18.25

Step-by-step explanation:

1/4 = 0.25

7 0
2 years ago
Read 2 more answers
Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
Anarel [89]
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
7 0
3 years ago
A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ? ​
jekas [21]
<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

  • Since 1 hour = 60 minutes..
  • 5 hours = 300 minutes ..

• Thus , The two given statements are :-

  • 14km -----------------> 25 minutes..
  • And, x km -------------> 300 minutes..

<h3><u>We know that , </u></h3>

  • The distance travelled by car and the time taken by the car is directly proportional to each other....

<h3>So , </h3>

\frac{14}{25}  =  \frac{x}{300}

= x = 168km

• Hence , Car can travel 168km in 5 hours ..

Hope this helps you :)

6 0
2 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. (If an answer does not exist, enter DNE.)
vodka [1.7K]

Answer:

absolute max is 120 and absolute min is -8

Step-by-step explanation:

Find critical numbers

f'(x) = 3x^2 - 12x + 9 = 0

= 3(x^2 - 4x + 3) = 0

3(x-3)(x-1) = 0

(x-3) = 0 or (x-1)=0

x = 1,3

Test them!

x<1     Sign of f' on this interval is positive

1<x<3 Sign of f' on this interval is negative

x>3    Sign of f' on this interval is positive

f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.

f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.

Test the endpoints to find the absolute max and min.

f(-1) = -8

f(1) = 12

f(3) = 8

f(7) = 120

The absolute maximum value of f is 120 and the absolute minimum value of f is -8.

7 0
3 years ago
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