This is one of the least few I promise.

PLEASE HELP I WILL MARK YOU BRAINLIEST<br><br> FIND THE AREA OF NUMBER 3 AND 4

scoray [572]

Answer:

3. 112.2 yd

4. 30m

Step-by-step explanation:

Number 3:

L × W (length × width) = A
18.7 × 6 = 112.2 yd

Number 4:

B × H (base × height) = A
6 × 5 = 30 m

I hope this helps!

8 0

3 years ago

Read 2 more answers

Interest calculated on a balance every three months is said to be compounded quarterly.

Mariulka [41]

Answer:

True

Step-by-step explanation:

The year is typically divided into equal different lengths of time. There are, for example, quarters, which divide the year by 4, i. e., in 4 periods of 3 months each. Other example are semesters, in this case, the year is divided into 2 periods of 6 months each. Taking this into account, an interest calculated on a balance every three months is compounded quarterly.

3 0

2 years ago

Caroline has a movie card worth $75 that her grandfather gave to her for her birthday. After seeing her first movie, the card’s

faust18 [17]

Answer:

f(m) = 75-8m

Step-by-step explanation:

She began with $75. After the first movie, she had $67 remaining; this means she spent

75-67 = $8

After the second movie, she had $59 remaining; she spent

67-59 = $8

After the third movie, she had $51 remaining; she spent

59-51 = $8

Each movie costs $8. Letting m represent the number of movies, this gives us 8m.

Since she is spending money, we subtract this from the original amount, $75; this gives us

f(m) = 75-8m

3 0

2 years ago

How to find the area of composite polygon that have a base of 16 meters height of 18 meters and a height of 11 meters.

LenaWriter [7]

The area of the composite polygon is:

$\boxed{A_{T}=376 \ m^2}$

<h2>Explanation:</h2><h2 />

Hello! remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll choose the figure below in order to illustrate this problem. A composite polygon is a polygon that can be divided into two or more basic shapes. So here we have a composite polygon formed by a triangle and a rectangle. So:

$A_{total}=A_{T} \\ \\ A_{triangle}=A_{tr} \\ \\ A_{rectangulo}=A_{r} \\ \\ \\ A_{tr}=\frac{b\times h}{2} \\ \\ b:Base \ of \ the \ triangle \\ \\ h:height \ of \ the \ triangle \\ \\ \\ A_{r}=B\times H \\ \\ B:base \ of \ the \ rectangle \\ \\ H:height \ of \ the \ rectangle$