Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
1 answer:
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
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Answer:
15,000$
Step-by-step explanation:
According to the information given, profits are divided equally into 4 parts
Since the total profit for the first month is 100,000$ each party will receive a sum of 25,000$. This means that Y also receives the same amount
Now if the profits were divided in proportion to the investments made we first find the proportion on investment made by Y.
The total investment made is 6000$ + 2000$ + 8000$ + 4000$ = 20,000$. Out of this, the amount invested by Y is 8000$
finding the proportional profit of Y
=40,000$
So Y receives 40,000 - 25,000 = 15,000 less