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DiKsa [7]
3 years ago
10

Please help me and the top is C What angle is this?

Mathematics
1 answer:
juin [17]3 years ago
8 0
Answer:it is a right angle I think I hope that helps
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Choose the correct description of each system of equations.<br> 3x + y = 3<br> x - 2y = 4
DENIUS [597]

Since we have a unique value of x and y, it shows that the system of the equation is consistent and independent.

Given the system of equation expressed as:

3x + y = 3

x - 2y = 4

Solve simultaneosly;

3x + y = 3 ............. 1 * 1

x - 2y = 4 ...............2 * 3

_________________________

3x + y = 3

3x - 6y = 12

Subtract

y-(6y) = 3 - 12

7y = -9

y = -9/7

Substitute y = -9/7 into the equation to get x

x - 2y = 4

x - 2(-9/7) = 4

x + 18/7 = 4

x = 4 -  18/7

x = 3/7

Since we have a unique value of x and y, it shows that the system of the equation is consistent and independent.

Learn more here: brainly.com/question/20052273

7 0
3 years ago
The parallelograms below are similar.
vova2212 [387]

Answer:

The length of sideAB=4

The measure of angle E=60

8 0
3 years ago
Read 2 more answers
HELP MEEEEEEEEEE<br> solve and show your work<br> 3x^2-14x-5
yanalaym [24]

Answer:

Step-by-step explanation:

x − 5 = 0   ⇒   x1 = 5

3x + 1 = 0   ⇒   x2 = −1

3

≈ −0.333333

Factorization:

(x − 5)(3x + 1) = 0

Standard form:

3x2 − 14x − 5 = 0

Extrema:

Min = (2.333333, −21.333333)

Answer:

( 3 x + 1 )  ( x − 5 )

5 0
3 years ago
Jarrods filing status on last years tax return was single, while paige’s was head of household. If both had taxable incomes of 8
Evgen [1.6K]

Answer:

C. Jarrod paid $1335 more than Paige in taxes

Step-by-step explanation:

just took the test

7 0
4 years ago
Which of the following equations is of the parabola whose vertex is at (2, 3), axis of symmetry parallel to the y-axis and p = 4
lora16 [44]

Answer:

option A.) y-3 = 1/16 (x-2)^2

Step-by-step explanation:

we know that

If the axis of symmetry is parallel to the y-axis, then we have a vertical parabola

The equation of a vertical parabola is equal to

4p(y-k)=(x-h)^{2}

where

(h,k) is the vertex

In this problem we have

(h,k)=(2,3)

p=4

substitute

4(4)(y-3)=4(4)(x-2)^{2}

16(y-3)=(x-2)^{2}

(y-3)=(1/16)(x-2)^{2}

8 0
3 years ago
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