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3 years ago

Help please due in 30 minutes

Mathematics

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

the last one

Step-by-step explanation:

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What is the answer to 2x^3(5x-1)

ikadub [295]

The answer is 10x^4 - 2x ^3

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3 years ago

Read 2 more answers

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=76°, and OP = 7.3 feet. Find the length of PQ to the nearest tenth of a foot..

PSYCHO15rus [73]

Answer: 7.1 feet

Step-by-step explanation: I guessed lol

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2 years ago

Y = 7/8u + 9, solve for u

vivado [14]

Answer:

$u=\frac{8y-72}{7}$

Step-by-step explanation:

Flip the equation.

$\frac{7}{8}u+9=y$

Add -9 to both sides

$\frac{7}{8}u+9(-9)=y(-9)$

$\frac{7}{8}u=y-9$

Divide both sides by 7/8

$u=\frac{8y-72}{7}$

hope this helps

3 0

3 years ago

which function is the inverse of f(x)=2x+3

LekaFEV [45]

Answer:

jssisvshdvdbd sjjsjdgdjd

Step-by-step explanation:

ususueuwgeieyevekeuecrjie r

4 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

3 years ago