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3 years ago

Sin²a+sin²a.tan²a=tan²a

Mathematics

1 answer:

wolverine [178]3 years ago

6 0

Answer:

# sin²A (1+tan²A)

# sin²A(sec²A)

# sin²A(1/cos²A)

# sin²A/cos²A=tan²A

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Help me please!!!!!!

lara [203]

Answer:

a. $b=2$

b. $b = 2a$

c. $a = \frac{1}{2}b\\$

d. $b = 10$

Step-by-step explanation:

Gradient is just another similar term for slope l, $m$ , and it can be calculated by $m = \frac{y_2 -y_1}{x_2 -x_1}\\$ where $x_n$ and 1 $y_n$ is the $xy$ -coordinates of point $n$

We let $(0,0)$ be point $1$ and $(a,b)$ be point $2$ , we can then write the equation:

$m = \frac{b -0}{a -0}\\ m = \frac{b}{a}$ .

It also says that the points are with a gradient of $2$ so $m = 2$ . We can then write the equation:

$2 = \frac{b}{a}\\$

Finding $b$ If $a = 1$ :

$2 = \frac{b}{a} \\ 2 = \frac{b}{1} \\ 2 = b \\ b = 2$

Writing an expression for $b$ in terms of $a$ .

$2 = \frac{b}{a} \\ \frac{b}{a} = 2 \\ \frac{b}{a} \times a = 2 \times a \\ b = 2a$

Writing an expression for $a$ in terms of $b$

$2 = \frac{b}{a} \\ \frac{b}{a} = 2 \\ \frac{a}{b} = \frac{1}{2} \\ \frac{a}{b} \times b = \frac{1}{2} \times b \\ a = \frac{1}{2}b$

Finding $b$ if $a = 5$

$2 = \frac{b}{a} \\ 2 = \frac{b}{5} \\ \frac{b}{5} = 2 \\ \frac{b}{5} \times 5 = 2 \times 5 \\ b = 10$

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3 years ago

The angles below form a linear pair. What is the measure of angle ABC?

skelet666 [1.2K]

Answer: 132 degrees

Explanation: a straight line has 180 degrees in it, take away the 48 leaves you with 132.

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Step-by-step explanation:

That is the answer to the question.

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3 years ago

3x^2-5=43 how do i solve this using the square root property

slava [35]

Answer:

x = 4

x = -4

Step-by-step explanation:

bro i dont know but i hope this help a little, sorry

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4 years ago

Use the four functions shown.

siniylev [52]

Only (I) is differentiable over (-5, 5) (and its entire domain, for that matter). This is because the exponential function is continuous and infinitely differentiable.

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3 years ago

Sin²a+sin²a.tan²a=tan²a​

Sin²a+sin²a.tan²a=tan²a