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Taya2010 [7]
3 years ago
8

12) Write an equation for a line with a slope of 4 and a y-intercept of -3. Us

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

Y=-3x+4

Step-by-step explanation:

Plug it into the y=mx+b formula.

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I need help I don’t understand! <br> What’s is the value of X?<br> A.58<br> B.62<br> C.65<br> D.68
natali 33 [55]

Answer:

B.62 is what I got for the answer

7 0
4 years ago
Two poles, A and B, are 12 meters apart. Pole A is 5 meters high. A rope 20 meters long is tied to the top of pole A and stretch
stepan [7]
The answer should be C, 21. I’ll attach a picture for explanation.
5 0
3 years ago
when your finding the area of a rectangle do you multiply the numbers around the perimeter or add them.
Flura [38]
When you are finding the area, you multiply the length x the width. So for example, we have a rectangle that the length is 6 feet and the width is 4 feet. So, first of all we multiply 6x4= 24. Since its area don't forget it is Square Feet (or any other type of measurement).

Hope it helps!
3 0
3 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
Standard form of 80000​
ki77a [65]

Answer:

8 × 10^4

Step-by-step explanation:

Count the number of zeros after 8.

3 0
3 years ago
Read 2 more answers
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