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Morgarella [4.7K]

3 years ago

6

2x=y+3 in slope intercept form

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

y=2x-3

Step-by-step explanation:

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if Donnie has 100 marbles and gives 25 away to Arthur and 35 to mike how many marbles does Donne have?

Marat540 [252]

Answer:

Step-by-step explanation:

100 MINUS 25 PLUS 35

5 0

3 years ago

Read 2 more answers

the slope of a line is 3/2 and the line contains the points (5,9) and (3, a). what is the value of a?

vivado [14]

Y = mx + b
slope(m) = 3/2
(5,9)...x = 5 and y = 9
now we sub and find b, the y int
9 = 3/2(5) + b
9 = 15/2 + b
9 - 15/2 = b
18/2 - 15/2 = b
3/2 = b
so ur equation is : y = 3/2x + 3/2.........(3,a)....so x = 3

y = 3/2(3) + 3/2
y = 9/2 + 3/2
y = 12/2
y = 6

so ur missing value is 6...a (or y) = 6

7 0

3 years ago

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

5 0

2 years ago

Please help with no links.

Wewaii [24]

Answer:

I think its B

I dont know if Im wrong

5 0

2 years ago

Find the circumference of a circle with diameter, d = 9.06m. Give your answer rounded to 2 DP

Olin [163]

C= 3.14d
C= 3.14 x 9.06
C= 28.45

5 0

2 years ago