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salantis [7]
3 years ago
7

Will is at a shirt sale where he can buy one and get a second one for 40 percent off. He wants to buy two shirts priced at $29 e

ach. How much will he pay?
Mathematics
2 answers:
Mice21 [21]3 years ago
7 0

Answer:

$46.4

Step-by-step explanation:

The offer is that if you buy one shirt, the second one will be 40% off the total price and so to calculate the total cost of the two shirts you just have to do the next equation:

X is the price of each shirt.

Y is the total cost.

Y= 2x-.40x

y=1.6 x

y= 1.6(29)

y=46,4

The total cost of the two shirts would be 46,4 dollars.

777dan777 [17]3 years ago
3 0

Answer:

he will pay $44.60

Step-by-step explanation:

first shirt is $29

second shirt is 40% off so it is $15.60

total for the two shirts is $44.60

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Tonya and Leo each bought a cell phone at the same time. The trade-in values, in dollars, of the cell phones are modeled by the
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Answer:

The answer is Tonya's phone had the greater initial trade-in value.

Leo's phone decreases at an average rate slower than the trade in value of Tonya's phone.

Step-by-step explanation:

Given

Tonya

f(x) = 490 * 0.88^x

Leo

x \to g(x)

0 \to 480

2 \to 360

4 \to 470

Solving (a): The phone with greater initial value

The initial value is when x = 0. So, we have:

f(x) = 490 * 0.88^x

f(0) = 490 * 0.88^0

f(0) = 490 * 1

f(0) = 490

From Leo's table

g(0) = 480

By comparison;

f(0) > g(0)

i.e.

490 > 480

<em>So: Tonya's had the greater initial trade-in value</em>

Solving (b): The phone with lesser rate

An exponential function is:

y = ab^x

Where:

b \to rate

For Tonya

b = 0.88

For Leo, we have:

(x_1,y_1) = (0,480)

(x_2,y_2) = (2,360)

So, the equation becomes:

y = ab^x

480 = ab^0 and 360 = ab^2

Solving 480 = ab^0, we have:

480 = a * 1

480 = a

a= 480

360 = ab^2 becomes

360 = 480 * b^2

Divide both sides by 480

0.75 = b^2

Take square roots

0.87 = b

b=0.87 -- Leo's rate

By comparison; Leo's rate is slower i.e. 0.87 < 0.88

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