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2 years ago

Can someone please help for brainlist

Mathematics

1 answer:

Paul [167]2 years ago

6 0

Answer:

keep going you got it

Step-by-step explanation:

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PLEASE HELP ILL GIVE YOU THE BRIANLYEST ANSWER ABC is shown on the coordinate gridMrs. Massey will reflect the triangle across t

I am Lyosha [343]

Answer:

The answer is c because there is not suppose to be a negative number

Step-by-step explanation:

6 0

2 years ago

What is the value of x in the equation 4 and StartFraction 3 Over 10 EndFraction minus (2 and two-fifths x + 5 and one-half) = o

musickatia [10]

Answer:

Step-by-step explanation:

Edge i think dont quote me on this plz

3 0

2 years ago

Drag and drop each expression into the box to correctly classify it as having a positive or negative product

AfilCa [17]

Following expressions will have negative product

$(\frac{1}{2})(-\frac{1}{2})\ and\ (-\frac{1}{2})(\frac{1}{2})$

Following expressions will have positive product

$(-\frac{1}{2})(-\frac{1}{2})\ and\ (\frac{1}{2})(\frac{1}{2})$

Further explanation:

We will see at each expression one by one

First expression is:

$(-\frac{1}{2})(\frac{1}{2})$

In the given expression one term is positive and one term is negative. The product of negative and positive terms is negative.

Second Expression is:

$(-\frac{1}{2})(-\frac{1}{2})$

Both terms are negative and the product of two negative terms is positive.

Third Expression is:

$(\frac{1}{2})(-\frac{1}{2})$

The expression has one positive and one negative term so the product will be negative

Fourth Expression is:

$(\frac{1}{2})(\frac{1}{2})$

Both terms are positive so the product will also be positive

Keywords: Product, Expressions

Learn more about expressions at:

#LearnwithBrainly

5 0

3 years ago

Urgent. Please show all work

myrzilka [38]

Answer:

$\displaystyle f'(x) = \frac{4}{x^2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Differentiation

Derivatives
Derivative Notation

The definition of a derivative is the slope of the tangent line: $\displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle f(x) = -\frac{4}{x}$

Step 2: Differentiate

[Function] Substitute in x: $\displaystyle f(x + h) = -\frac{4}{x + h}$
Substitute in functions [Definition of a Derivative]: $\displaystyle f'(x) = \lim_{h \to 0} \frac{-\frac{4}{x + h} - \big( -\frac{4}{x} \big)}{h}$
Simplify: $\displaystyle f'(x) = \lim_{h \to 0} \frac{4}{x(x+ h)}$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle f'(x) = \frac{4}{x(x+ 0)}$
Simplify: $\displaystyle f'(x) = \frac{4}{x^2}$