Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Answer:
Squaring both the sides, we get a quadratic and solving it, we find that the possible values of x are -7 and -4.
Step-by-step explanation:
The expression can be written as √(x+8) - 6 = x. Take 6 on the other side and square both the sides.
[√(x + 8)]² = (x + 6)²
x + 8 = x² + 12x + 36
x² + 11x + 28 = 0
x² + 7x + 4x + 28 = 0
(x + 7)(x + 4) = 0
x = -7 and x = -4
The possible values of x are -7 and -4.
For more explanation, refer the following link:
brainly.com/question/10572241
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0.004 is one tenth of 0.04 or 0.04 is ten times 0.004
Answer:
x=2-1/2y
Step-by-step explanation:
12x+6y=24
12x=24-6y
x=24/12-6/12y
x=2-1/2y