I can only give possible combination of the ages. Had the sum of the ages been given, then the 3 specific numbers would have been derived.
We need to do prime factorization of 72.
72 ÷ 2 = 36
36 ÷ 2= 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 1 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible combinations:
1 x 8 x 9 = 72 1 + 8 + 9 = 18
1 x 4 x 18 = 72 1 + 4 + 18 = 23
2 x 4 x 9 = 72 2 + 4 + 9 = 15
3 x 4 x 6 = 72 3 + 4 + 6 = 13
Answer:
The distinct factors of 75 are 1, 3, 5, 15, 25, 75.
Step-by-step explanation:
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We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
Answer:
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Step-by-step explanation:
Answer:
1. 54 2. 2$
Step-by-step explanation:
1. total students= 331
n.o of buses=6
now,
total no of students travelling through bus,
=331-7
=324
now,
324÷6
=54
2.
total money=24$
remaining money= 10$
spent money on pencil= 24-10$
= 14$
now,
7 pencils cost= 14$
1 pencil cost= 14÷7$
=2$
