All categories

3 years ago

How many terms in 9a+11p

Mathematics

2 answers:

Naddik [55]3 years ago

7 0

Answer:

2 terms

Step-by-step explanation:

Terms are nothing but the mixtures of co-effecients and their variables..

Here, 9a is one term while 11p is the other

AURORKA [14]3 years ago

7 0

Answer:

Step-by-step explanation:

9a is a term and 11p is a term.

You might be interested in

The picture i need help with this answer. the problem is in the picture

OlgaM077 [116]

Answer:

Step-by-step explanation:

4 0

2 years ago

Use estimation to check the answer to this story problem.

katovenus [111]

Here, the answer would be: 765 * 11 = 8415 [ About 8 thousands ]

In short, Your Answer would be Option C) The answer should be about 8,000 yards. The student's answer is not correct.

Hope this helps!

5 0

3 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

METHOD - I

Sin² C + Cos² C = 1

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$

Tan C = $\frac{3}{4}$ 

METHOD - II

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

∵ ΔABC is Right triangle.

∴ By Pythagorean Theorem-

AB² + AC² = BC²

AC² = BC² - AB²

AC² = 5² - 3²

AC² = 25 - 9

AC² = 16

AC ( Base) = 4

Since,

Tan C = $\frac{Height}{Base}$ 

Tan C = $\frac{AB}{AC}$

Hence Tan C = $\frac{3}{4}$ 

4 0

3 years ago

What is 14.876 - 4.96

d1i1m1o1n [39]

Answer:

9.916 is the answer

4 0

3 years ago

Read 2 more answers

Please someone help me I will give brainliest

zubka84 [21]

Answer:

Hey buddy whatsup? All good

Coming to the question fig 1 and 3 aren't functions

Coz.... Reason for fig 1... Every distinct element of domain must have a unique element in codomain, but in this fig the same element has more than two unique elements which is a relation not a function.

Reason for fig 3 every element in domain must have an unique element in codomain but in this fig the element c doesn't have any unique element hence it isn't a function.....

Thank you

6 0

3 years ago

Read 2 more answers