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Elenna [48]
3 years ago
10

Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.

Mathematics
1 answer:
g100num [7]3 years ago
6 0
<span>1. If it is intersection then it SHOULD be included in both the sets right? Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!! So A={51,53,57,59,61......99} B={55,60,65,70.......95} [We stop till 100 because set A has no such element] So what is A ∩ B here? A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}

</span>
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45 1/3 x 8 1/9 = m<br> m = ?<br> If you answer I will rate you 5 stars. Thank you!
Nastasia [14]

Answer:

367 19/27

Step-by-step explanation:

Use symbolab bruv, its easy.

7 0
3 years ago
PLZ HELP ME!!!!!
gayaneshka [121]

Answer:

1. (0, 1)


Step-by-step explanation:

Put x = 0 then work out the values of y:0

y = 3^0 = 1  y-intercept is (0,1)

y = 0,25^x , y = 0.25^0 = 1

All the others are done in same way



4 0
3 years ago
Can someone solve these for me
tatuchka [14]

Answer:

0.66 and 33/50

62.5% and 5/8

0.75 and 3/4

120% and 1 1/5

0.005 and 1/200

3.75 and 375%

I hope that is correct and helps you! :)

Step-by-step explanation:

8 0
3 years ago
Question 6 of 10
ElenaW [278]

150,000

This is the answer for apex!!!

6 0
3 years ago
Read 2 more answers
Can someone please explain how to do these?
Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

For the first limit, plug in x=8 in the expression (9x-3), that's the answer for linear equations and limits.

So we have:

9x-3\\9(8)-3\\72-3\\69

The answer is 69


For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5

So the answer is 5

3 0
3 years ago
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