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2 years ago

Need help with angle solving

Mathematics

1 answer:

laiz [17]2 years ago

8 0

Step-by-step explanation:

corresponding angles (CA)

Alternative interior angles (AIA)

co interior angles (CIA)

question 1 angles =

5 + 3 = 180 ( CIA)

83⁰ + 3 = 180

angle 3 = 180 - 83⁰

angle 3 = 97

angle 8 = angle 3.... CA

angle 8 = angle 16 ....CA

ANGLE 16 = ANGLE 12.....CA

angle 5 = angle 13 ....CA

ANGLE 3 = Angle 6......AIA

ANGLE 5 = ANGLE 4.......AIA

ANGLE 4 = ANGLE 7......CA

ANGLE 6 = ANGLE 1......CA

ANGLE 13 = ANGLE 9......CA

ANGLE 12 = ANGLE 14.....AIA

ANGLE 13 = ANGLE 11.....AIA

ANGLE 14 = ANGLE 10.......CA

ANGLE 11 = ANGLE 15

NOW JUST PUT THE VALUES GIVEN IN QUESTION AND AT THE TOP OF MY ANSWER IN EACH CASE AND UR DONE.....

QUESTION 2 :

ANGLE 1 = ANGLE 7 .......AIA

2X + 40 = 6X - 20

40 + 20 = 6X - 2X

60 = 4X

60/4 = X

15⁰ = X

SO, ANGLE 7 = 6× 15 -20 = 90 - 20 = 70⁰

AND, ANGLE 1 = 2 × 15 + 40 = 30 + 40 = 70⁰

ANGLE 7 = ANGLE 3 ......CA

ANGLE 3 = ANGLE 5 .....AIA

ANGLE 3 + ANGLE 6 = 180 .....CIA

70 + ANGLE 6 = 180⁰

ANGLE 6 = 180 - 70⁰ = 110⁰

angle 2 = Angle 6

ANGLE 2 = ANGLE 8.....AEA ALTERNATIVE EXTERIOR ANGLE

ANGLE 8 = ANGLE 4

NOW, JUST PUT THE VALUES I HAVE WRITTEN ABOVE ACCORDINGLY IN EACH CASE....

Did I really jst got 15 points for this (ノ｀Д´)ノ彡

HEHEEE JK:)

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3 years ago

The sum of the ages of Kristen and Ben is 32. Four years ago Kristen was twice as old as Ben. How old are they both now?

Elan Coil [88]

Let us say that:

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B = age of Ben

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eqtn 2: (K – 4) = 2 (B – 4)

Simplifying eqtn 2:

K – 4 = 2 B – 8

K = 2 B – 4

Plugging in this to eqtn 2:

(2 B – 4) + B = 32

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3 years ago

3s+2t−3 =c<br> −7s−5t =4<br>

irinina [24]

Answer:

−4

s−t+

−4

Step-by-step explanation:

Let's solve for c.

3s+2t−3c−7s−5t=4

Step 1: Add 4s to both sides.

−3c−4s−3t+4s=4+4s

−3c−3t=4s+4

Step 2: Add 3t to both sides.

−3c−3t+3t=4s+4+3t

−3c=4s+3t+4

Step 3: Divide both sides by -3.

−3c

−3

4s+3t+4

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2 years ago

Please help i beg i never get these right

Anuta_ua [19.1K]

Answer:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

Step-by-step explanation:

Given

$\sin(105^o)$

Required

Solve

Using sine rule, we have:

$\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)$

This gives:

$\sin(105^o) = \sin(60 + 45)$

So, we have:

$\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)$

In radical forms, we have:

$\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}$

$\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}$

Take LCM

$\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}$

Rewrite as:

$\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}$

Hence:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

3 0

2 years ago

Need help with angle solving​

Need help with angle solving