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allochka39001 [22]

3 years ago

6

A and B are the subsets of a universal set U. If U = {1,2,3,4,5,6,7,8,9,10} A={1,2,3,5,7,9} and B ={1,2,3,6}, show that AUB comp

lement=AΠB complement

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer:

AUB= {1,2,3,5,6,7,9}

AnB={1,2,3}

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Charra [1.4K]

Answer:

what are the other colors?

Step-by-step explanation:

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Vsevolod [243]

Answer:

$(a+2b^{2} )(a-2b^2)$

Step-by-step explanation:

You have what is called "perfect squares" so you can use the "difference of squares formula to factor:

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3 years ago

Indicate a general rule for the nh term of this sequence.<br> 12a, 15a, 18a, 21a, 24a,...

adelina 88 [10]

Answer:

The general rule for the nth term of this sequence will be:

$a_n=3na+9a$

Step-by-step explanation:

Given the sequence

12a, 15a, 18a, 21a, 24a,...

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

Here,

a₁ = 12a

computing the differences of all the adjacent terms

d = 15a-12a = 3a, d = 18a-15a=3a, d=21a-18a=3a, d=24a-21a=3a

using the nth term formula

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = 12a, d = 3a

$a_n=12a+\left(n-1\right)3a$

$=12a+3na-3a$

$=3na+9a$

Therefore, the general rule for the nth term of this sequence will be:

$a_n=3na+9a$

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3 years ago

The circumference of an NBA-approved basketball is 29.6 in. Given that the radius of Earth is about 6400 km, how many basketball

ella [17]

Answer:

167,886,383 basketballs

Step-by-step explanation:

We are asked to find how many basketballs would take to circle around the equator. We have given the earth's radius. So, we need the formula to obtain it's perimeter. Thus:

$Perimeter = Pi*diameter [m]\\Where Pi = 3.14$

Earth's diameter is simply radius*2. It means:

$P= 3.14*6400*2 = 40,192 [km]$

On the other hand, we have a basketball crcumference; however, we need to obtain its diameter so that we can later calculate how many basketballs fit on earth's equator by simply dividing earth's circumference by a basketball's diameter.

Diameter of a basketball:

$D= Perimeter /Pi [m]$

We need to change units to fit in the international system.

29.6 in to cm = $29.6*2.54 = 75.184 [cm]$

Then:

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We have to convert earth's perimeter in km to cm:

$Equator=40192[km]*100000=4,019,200,000 [cm]$

Finally, dividing total earth's circumference by a basketball diameter:

$Totalbasketballs=4,019,200,000/23.94= 167,886,383 [basketballs]$

8 0

3 years ago