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horsena [70]
3 years ago
8

Given a linear time series trend, Y' = 5.2 + 3.1t, what is the forecast for 2002 if the time series started in 1995?

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

26.9

Step-by-step explanation:

t=7

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Evaluate the expression 5 % (8 + 6 – 2).
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Answer:

12*5%=0.6

Step-by-step explanation:

8+6=14-2=12

12*5%=0.6

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Is 16.275 greater then 16.28
Svetlanka [38]

Answer:

no

Step-by-step explanation:

16.28 can also be written 16.280 (you could add as many zeros to the end as you want its still the same number)

280 is bigger than 275

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The region bounded by y = e−x2, y = 0, x = 0, and x = b (b > 0) is revolved about the y-axis. (Round your answers to three de
kari74 [83]

Answer:

0.982 * \pi  = 3.085 cubic units

Step-by-step explanation:

To find the volume of the solid generated by a region that is bounded by lines where x = 0 , x (b) = 2 we apply the formula given in the attachment below  

the required region boundaries are

y = e^-x2 , y = 0 ,  x = 0,  x = b ( b >0)

attached below is a detailed solution of the problem

6 0
3 years ago
Two nonadjacent angles formed by two intersecting lines are
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Two vertical angles are formed. These angles are also equal to each other.
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3 years ago
Drag each tile to the correct box.
Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0
3 years ago
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