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2 years ago

What's the midpoint of a line segment joining the points (5, –4) and (–13, 12)?

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

The answer is A. (-4,4)

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MARKING BRAINLIEST

xz_007 [3.2K]

Answer:

secondary

Step-by-step explanation:

mixing two primary colors together always makes a secondary

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2 years ago

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Gary needs to solve 120 problems by a certain day. He calculated, that to finish all the problems in time, he needs to solve 5 p

kozerog [31]

Answer:

To be done in time, he would need to solve 6 questions per day on the days that he is not on trip

Step-by-step explanation:

If he solves the problems 5 per day, the total number of days that would be required to finish solving the problem would be 120/5 = 24 days

Now, he has 4 free days which would be for a family trip. The number of questions that he would miss during those trip days will be 4 * 5 = 20 questions

Now since he wants to still finish on time, what is needed to be done is to share the 20 left overs amongst the 20 days which he has to work

This makes a total of 1 question per day

Adding this to the 5 questions per day he has before will be = 6 questions per day

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2 years ago

What is the volume of the rectangular prism?

Rufina [12.5K]

Answer:

$\large\boxed{Q1.\ 80\ cm^3}\\\boxed{Q2.\ 45\ in^3}\\\boxed{Q3.\ 48\ m^3}\\\boxed{Q4.\ A,\ D}\\\boxed{Q5.\ 96\ in^3}$

Step-by-step explanation:

$\text{The formula of a volume of a rectangular prism:}\\\\V=lwh\\\\l-length\\w-width\\h-height$

$\bold{Q1}\\\\l=10\ cm,\ w=4\ cm,\ h=2\ cm\\\\V=(10)(4)(2)=80\ cm^3\\\\\bold{Q2.}\\\\l=5\ in,\ w=3\ in,\ h=3\ in\\\\V=(5)(3)(3)=45\ in^3\\\\\bold{Q3.}\\\\l=4\ m,\ w=2\ m,\ h=6\ m\\\\V=(4)(2)(6)=48\ m^3\\\\\bold{Q4.}\\\\V=120\ ft^3\\\\\bold{A:(5)(4)(6)=120}\\B:\ (7)(7)(6)=294\\C:\ (3)(6)(4)=72\\\bold{D:\ (10)(3)(4)=120}\\\\\bold{Q5.}\\\\l=8\ in,\ w=4\ in,\ h=3\ in\\\\V=(8)(4)(3)=96\ in^3$

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2 years ago

√48a^4 b^5 c^3 d simplify and keep it in radical form

Morgarella [4.7K]

I will assume the square root extends all the way across.

$\sqrt{48a^4b^5c^3}$

$\sqrt{2^4\cdot3\cdot a^4b^5c^3}$

$\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}$

$\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}$

$4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}$

$\boxed{4a^2b^2c\sqrt{3bc}}$

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3 years ago

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nikklg [1K]

Answer:

4260

Step-by-step explanation:

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3 years ago

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