Question

What is the diameter of the circle: x^2+y^2=16 ?

Answer 1

Answer:

The diameter of this circle is equal to 8

Step-by-step explanation:

The standard form of a circle is equal to x^2 + y^2 = r^2. As this equation shows x^2 + y^2 = 16, all we have to do is find the square root of 16, which is 4. This means that 4 is the radius of the circle and that 2 * 4 = 8, which is the diameter of the circle.

Because of this, the diameter of this circle is equal to 8.